cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California price USD/pack.
cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California - today, latest wholesale market price per USD/pack from day 2018-03-28.
Commodity: cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California market trend raport, analysis and information.
| Newest price | 14 - 15 |
| Previous price | 16 - 18 |
| Highest price | 18 |
| Lowest Price | 14 |
| Quotes range | 2016 - 2018 |
| Unit | USD/pack |
| Frequency | Irregular |
Data source: product quotes, statistic informations, websites, stock quotes
Newest price
14.50 USD/pack
Download our new
Husfarm App
Stay up to date with the current prieces of agricultural products all over the world.
How much does cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California cost?
Historical prices, quotes range 2016 - 2018 cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California - sheet price.
| Date | Unit | Min price | Max price | Currency | Stock |
|---|---|---|---|---|---|
| 2018-03-28 | pack | 14 | 15 | USD | Philadelphia Terminal Market |
| 2018-03-02 | pack | 16 | 18 | USD | Philadelphia Terminal Market |
| 2018-03-01 | pack | 16 | 18 | USD | Philadelphia Terminal Market |
| 2016-12-21 | pack | 14 | 15 | USD | Philadelphia Terminal Market |
How to sell cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California agricultural products online, and get best price?
Are you looking for cauliflower cartonsfilmwrapped white 12s condition(fair) appearance(fair) California , do you want to buy?
Post an ad for FREE!
New offerWhere to buy?
Enterprise-Grade Chicken Mini Game Script for Building a Profitable Casino Platform
City: Madrid
Price: 11.0 $
Chicken Road 2.0 Game Script at Minimal Cost for Sustainable iGaming Success
City: Berlin
Price: 1.0 $
Enter the iGaming Industry with 1XBet Clone Script – Affordable and Scalable Solution
City: Berlin
Price: 1.0 $